a)diagram

1.Lg5*f4-e3[+bPg5]  
2.Le3*g5-h6[+bPe3]  
3.Lh6*e3-d2[+bPh6]  
4.Ld2*e2-f2[+bPd2]  
5.Lf2*d2-c2[+bPf2]  
6.Lc2*f2-g2[+bPc2]  
7.Lg2*c2-b2[+bPg2]  
8.Lb2*g2-h2[+bPb2]  
9.Lh2*h6-h7[+bPh2] 
10.Lh7*h2-h1[+bPh7] 
11.Lh1*h7-h8 
12.Lh8*b2-a1 ==

b)wLg5-->f5 

1.Lf5*f4-f3[+bPf5]  
2.Lf3*f5-f6[+bPf3]  
3.Lf6*f3-f2[+bPf6]  
4.Lf2*e2-d2[+bPf2]  
5.Ld2*f2-g2[+bPd2]  
6.Lg2*d2-c2[+bPg2]  
7.Lc2*g2-h2[+bPc2]  
8.Lh2*c2-b2[+bPh2]  
9.Lb2*f6-g7[+bPb2] 
10.Lg7*b2-a1[+bPg7] 
11.La1*g7-h8 
12.Lh8*h2-h1 ==

A graphical representation of solution a) are two isosceles impedance triangles with the hypotenuses on two different diagonals (b2-h8 and d2-h6). In the solution b) are the result two isosceles impedance triangles again, but the hypotenuses are on the same to the diagonal (b2-f6 and b2-h8).(Author)