a) diagram     1.2....
1.nEAg5*e5 nEAd5-e4[+nGf4]   2.nEAe5*f6 nGf4*f6[+nEAf8]
3.nEAf8-g6[+nEAg4][+bKh5] + nEAf5-f3[+wKf5] #
1.nEAg5*e5 nEAf5-e6[+nGd6]   2.nEAe5*f6 nGd6*f6[+nEAh6]
3.nEAh6-f7[+nEAd7][+bKe8] + nEAe6-c6[+wKe6] #

b) nGe5-->h5     1.2.... 
1.nGh5*f5 nEAd5-f4[+nEAh4]   2.nEAh4*f4 nEAg5*f4[+nEAe3]
3.nEAf6-g5[+nEAg3][+bKh4] + nEAf4-f2[+wKf4] #
1.nGh5*f5 nEAg5-g7[+nEAf7]   2.nEAf6-e7 nEAf7-g5
3.nEAd5-f6[+bKh6] + nEAf6-f8[+wKf6] #

c) nEAf6-->c4     2.1.... 
1.nGe5-c5 nEAd5-d3   2.nEAf5-c6 nEAg5*c4
3.nEAc6-b5[+nEAb3][+bKa4] + nEAc4-c2[+wKc4] #
1.nEAf5-e4 nEAg5*e4   2.nGe5-e3[+nEAe2] nEAe4*c4
3.nEAd5-d3[+nEAc2][+bKd1] + nEAd3-b3[+wKd3] #

Award: Variantim No.81, 8/2020, Judge: Hans Gruber
This problem is an intellectual challenge on the one hand
(very complicate conditions and pieces:
it is difficult not to mix the just captured piece
and the to-be-reborn one, as in most cases
they are ofthe same nature), but one the other hand
it shows a six fold echo which is a big achievement.
(Judge: Hans Gruber )