Chess problem details
 Chess problem diagram
Category: Fairy
Type: sd#n
Stipulation(s): 24 W & h#1
Magazine: ChessProblems.ca Bulletin 18, 6/2020, Pr. T493
Year of Publishing: 2020
Conditions:
Alphabetic + PWC + Einstein
Solution: Click here for full details...

1.nPa2-a4   2.nPa4-a5   3.nPa5-a6   4.nPa6-a7   5.nPa7*b8=S[+nPa7]  
6.nPa7*b8=S[+nSa7]   7.nSa7-c6=P   8.nPb2-b4   9.nPb4-b5  10.nPb5*c6=S[+nPb5] 
11.nPb5*c6=S[+nSb5]  12.nSb5-d6=P  13.nSb8-a6=P  14.nPa6-a7  15.nPc2-c4 
16.nPc4-c5  17.nPc5*d6=S[+nPc5]  18.nPc5*d6=S[+nSc5]  19.nSc5-b3=P 
20.nPb3-b4  21.nPb4-b5 22.nPb5-b6  23.nPb6*a7=S[+nPb6]  24.nSa7*c6=B[+nSa7]
& 1.Ka8-b8  nSa7*c6=B[+nBa7] #

Note:also works as ser-#23:
1.nPa2-a4   2.nPa4-a5   3.nPa5-a6   4.nPa6-a7   5.nPa7*b8=S[+nPa7]  
6.nPa7*b8=S[+nSa7]   7.nSa7-c6=P   8.nPb2-b4   9.nPb4-b5  10.nPb5*c6=S[+nPb5] 
11.nPb5*c6=S[+nSb5]  12.nSb5-c7=P  13.nSb8-a6=P  14.nPa6-a7  15.nPc2-c4 
16.nPc4-c5  17.nSc6*a7=B[+nPc6]  18.nBa7*c5=R[+n

Comments:
A fourfold sequence of capture - knight pairs are created three times, a bishop pair is created once. Note: also works as ser-#23. (Author)
Tags:
Neutral Pawns, Circuit, Kniest, capture cycle, reciprocal capture, Klasinc
        

       

       

       
© Jaroslav Stun, 2007, Voniak Chess dBase