Detail of chess problem

Chess problem details


	Category:	Fairy
	Type:	ser-==n
	Stipulation(s):	ser-==101 G=Grasshopper LO=Locust
	Magazine:	ChessProblems.ca Bulletin 19, 31.12.2020, Pr. T514
	Year of Publishing:	2020

	Conditions:
	Sentinelles Pion adverse Symmetry Circe Grid special

	Solution:	Click here for full details...
	1.LO×f3-e4(+g2) 2.LO×g2-h1(b7;+e4) 3.LO×e4-d5 4.LO×d2-d1(+d5) 5.LO×d5-d6(e4) 6.LO×d7-d8(+d6) 7.LO×d6-d5(e3) 8.LO×e4-f3(d5) 9.LO×e2-d1(Sd7;+f3) 10.LO×f3-g4 11.LO×d7-c8(Ge2;+g4) 12.LO×b7-a6(g2) 13.LO×c6-d6(LOf3;+a6) 14.LO×f6-g6(+d6) 15.LO×d6-c6(+g6) 16.LO×d5-e4(+c6) 17.LO×e7-e8(Gd2;+e4) 18.LO×g6-h5(b3) 19.LO×c5-b5(f4) 20.LO×c6-d7(+b5) 21.LO×g4-h3(+d7) 22.LO×g2-f1(b7) 23.LO×e2-d3 24.LO×e4-f5(d5) 25.LO×d5-c5(e4) 26.LO×e3-f2(d6) 27.LO×d2-c2(Ge7) 28.LO×b3-a4(g6) 29.LO×b5-c6(g4) 30.LO×d7-e8(e2) 31.LO×e7-e6(Gd2) 32.LO×g6-h6(b3) 33.LO×f4-e3(c5) 34.LO×f3-g3(LOc6) 35.LO×d6-c7(e3) 36.LO×b7-a7(g2) 37.LO×a6-a5(h3) 38.LO×c5-d5(f4) 39.LO×d2-d1(Ge7) 40.LO×e2-f3(d7) 41.LO×g2-h1(b7) 42.LO×h3-h4(a6) 43.LO×e7-d8(Gd2) 44.LO×d7-d6(e2) 45.LO×f4-g3(c5) 46.LO×e3-d3(d6) 47.LO×d2-d1(Ge7) 48.LO×b3-a4(g6) 49.LO×a6-a7(h3) 50.LO×b7-c7(g2) 51.LO×e7-f7(Gd2) 52.LO×g6-h5(b3) 53.LO×g4-f3(b5) 54.LO×e4-d5(+f3) 55.LO×d2-d1(Ge7) 56.LO×d6-d7(e3) 57.LO×e7-f7(Gd2) 58.LO×f3

	Comments:
	T514: It’s clear after the first moves that the right possibility of putting the white locust in the final position is on the b-column (not on the 2nd row, nor on the diagonal b1-h7). The initial moves release the fields to create pairs of fields for Symmetric Circe rebirth, especially d2 - e7, d7 - e2, c6 - f3, b7 - g2 and others. Releasing one field from a pair is important not only for the functioning ofthe Symmetric Circe, but also for moving the white locust by entering these fields. Field d2 can block the grasshopper “able to move”, because by its departure it leaves behind a white pawn. It gives check to the black king. Release of fields for Symmetric Circe rebirth circuits: f3 (immediately on the first move), g2 (2.Le4×g2-h1 (Pb7; +Pe4)), d2(4.Ld5×d2-d1 (+Pd5)), d7 (6.Ld6×d7-d8 (+Pd6)), e2 (23.Lf1×e2-d3). (Author)
	Tags:
	Circuit